Answer:
The numerical length of BD is 20 units
Step-by-step explanation:
Let us solve the question
∵ Point C lies on the line segment BD
→ That means C divides BD into 2 parts
∴ C divides BD into 2 parts BC and CD
∴ BD = BC + CD
∵ BD = 5x
∵ BC = 4x
∵ CD = 4
→ Substitute them in the equation above
∴ 5x = 4x + 4
→ Subtract 4x from both sides
∵ 5x - 4x = 4x - 4x + 4
∴ x = 4
→ Substitute the value of x in the expression of BD
∵ BD = 5x
∵ x = 4
∴ BD = 5(4) = 20
∴ The numerical length of BD is 20 units
Answer:
a 0
b) 0.9
c) 0.85
d) 0.25
e) 0.1
f) 0.0375
Step-by-step explanation:
a)
As A and B are two disjoints events, then P(A and B) is
P(A and B)=0
b)
As A and B are two disjoints events, then P(A or B) is
P(A or B)=P(A)+P(B)
P(A or B)=0.15+0.75=0.9
c)
P(not A)=1-P(A)
P(not A)=1-0.15=0.85
d)
P(not B)=1-P(B)
P(not B)=1-0.75=0.25
e)
P(not (A or B))=1-P(A or B)
P(not (A or B))=1-0.9=0.1
f)
P(A and (not B))=P(A)*P(not B)
P(A and (not B))=0.15*0.25=0.0375
Answer: m = -1
Step-by-step explanation:
m = slope
The slope is 1/-1 which is just -1.
Hope this helps!
78.00 = 59.99+0.10x
10.01=0.10x
x= 180.1 so she can send 180 texts plus the 100 free ones for a total of 280 texts
double check: 180 x 0.10 = 18.00 + 59.99 = 77.99
There are 400 students in a school. In Zachary's class, 18 out of 30 students participate in after-school activities. Based on Zachary's class, about how many students in the school are predicted to participate in after-school activities?
