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2 years ago

Simplify the expression. x^4/ x^7 a x-11 b x-3 c x11 b x3

Mathematics

2 answers:

maksim [4K]2 years ago

4 0

Answer:

Step-by-step explanation:

$\frac{x^4}{x^7} =x^4 \times x^{-7} =x^{4-7} =x^{-3}$

VARVARA [1.3K]2 years ago

3 0

Answer:

Step-by-step explanation:

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The vertices of figure BCDE have coordinates B(4, 4), C(−4, 4), D(−4, −4), and E(4, −4). The vertices of figure BꞌCꞌDꞌEꞌ have co

nikdorinn [45]

C.) A <span>dilation with a scale factor of 4, with center of dilation at the origin

Here, You can either draw the figure or compare the coordinates,
B = (4, 4) then B' = (1, 1)
C = (-4, 4) then C' = (-1, 1)
D = (-4, -4) then D' = (-1, -1)
E = (4, -4) then E' = (1, -1)

So, Every coordinate is reducing by 4th factor... Hence, dilation factor is 4 about the origin

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4 0

3 years ago

Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.

fgiga [73]

Answer:

QN = 3√7
OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

DQ = (3 units)·3 = 9 units

KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

KI² = KO² +OI²

4² = 3² +OI²

OI = √(16 -9)

OI = √7

QN = 3·OI = 3√7

8 0

3 years ago

£940 is divided between gavin, jim & Krutika so that gavin gets twice as much as jim, and jim gets three times as much as kr

Zielflug [23.3K]

Answer:

$282

Step-by-step explanation:

We can think of it as an equation system. Lets find out the equations.

There are 3 people: Krutika, Gavin and Jim. Lets call k Kutrika's money and g and j Gavin's and Jim's money respectively.

So, as Gavin gains twice as Jim we can say that:

g = 2j

Then, as Jim gets 3 times more than Kutrika:

j = 3k

And, as the whole sum is 940:

k + j + g = 940.

Notice that both Kutrika's and Gavin's money have a relation to Jim's money, so we can try to write them as function of Jim's money.

If we part from j = 3k and divide both sides by 3:

j/3 = k

So, using this last equation and g = 2j, replacing in the equation that sums the money of everyone:

k + j + g = 940

j/3 + j + 2j = 940

Putting together all the terms that have j imply using 3 as common denominator:

j/3 + 3j/3 + 6j/3 = 940

10j/3 = 940

Dividing both sides by 10/3 (or multiplying by 3/10):

j = 940/ (10/3) = 282

So, Jim has $282. Now we can use the relations we defined to find k and g:

k = j/3 =$94

g = 2j = $564

4 0

3 years ago

(x^3−7x−6) : (x−4)<br> Kan someone solve this for me, and show how to get it?

Vladimir79 [104]

Answer:

x = 3 or x = -1 or x = -2

Step-by-step explanation:

Solve for x:

(x^3 - 7 x - 6)/(x - 4) = 0

Hint: | Multiply both sides by a polynomial to clear fractions.

Multiply both sides by x - 4:

x^3 - 7 x - 6 = 0

Hint: | Factor the left hand side.

The left hand side factors into a product with three terms:

(x - 3) (x + 1) (x + 2) = 0

Hint: | Find the roots of each term in the product separately.

Split into three equations:

x - 3 = 0 or x + 1 = 0 or x + 2 = 0

Hint: | Look at the first equation: Solve for x.

Add 3 to both sides:

x = 3 or x + 1 = 0 or x + 2 = 0

Hint: | Look at the second equation: Solve for x.

Subtract 1 from both sides:

x = 3 or x = -1 or x + 2 = 0

Hint: | Look at the third equation: Solve for x.

Subtract 2 from both sides:

Answer: x = 3 or x = -1 or x = -2

3 0

3 years ago

In a standard normal distribution, the a. mean and the standard deviation are both 1 b. mean is 0 and the standard deviation is

sergij07 [2.7K]

Answer:1cd.2

Step-by-step explanation:

Distrubution=0-1c

8 0

2 years ago