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xxTIMURxx [149]

3 years ago

10

Simplify the following. (7+5i)^2−(3+2i)=

1 answer:

Ivahew [28]3 years ago

7 0

Answer:

hope that will help you

You might be interested in

A principal randomly chose 30 students from grade 8. Of these students, 9 were wearing watches. Based on this information, what

hram777 [196]

Answer:

im pretty sure 36

Step-by-step explanation:

if you do 120 devided by 30 you get 4, then u just multipy by 9 which is 36.

5 0

3 years ago

58 = –2(m + 4) + m –22 –50 –66 –33

Anika [276]

Assignment: $\bold{Solve \ Equation: \ 58=-2\left(m+4\right)+m}$

<><><><><>

Answer: $\boxed{\bold{m=-66}}$

<><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><>

[ Step One ] Switch Sides

$\bold{-2\left(m+4\right)+m=58}$

[ Step Two ] Expand $\bold{-2\left(m+4\right)+m}$

$\bold{-m-8}$

[ Step Three ] Rewrite Equation

$\bold{-m-8=58}$

[ Step Four ] Add 8 To Both Sides

$\bold{-m-8+8=58+8}$

[ Step Five ] Simplify

$\bold{-m=66}$

[ Step Six ] Divide Both Sides By -1

$\bold{\frac{-m}{-1}=\frac{66}{-1}}$

[ Step Seven ] Simplify

$\bold{x=-66}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

3 0

4 years ago

Read 2 more answers

If you use exactly eight cups of cauliflower to make 6 veggie burritos and if you continue to make burritos using the same recip

Vitek1552 [10]

Answer:

9 burritos

Step-by-step explanation:

We can use ratios to solve

8 cups 12 cups

---------- = -----------------

6 burritos x burritos

Using cross products

8x = 6*12

8x = 72

Divide by 8

8x/8 =72/8

x = 9

9 burritos

7 0

3 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

72 is equal to 80% of a number n. Write and solve and equation to find n. Write the percent as a decimal.

valentina_108 [34]

Well I'm not sure what the answer would be since I'm not that smart but I did get the answer of 90, I did this by dividing 72 by 80 which equals .9 and I multiplied that by 100 and got 90.

4 0

3 years ago

Read 2 more answers