7/5 simplafied please help me

A jar contains nickles and pennies. There are 56 coins in the jar in all. The total value the total value of the coins are $1.52

timofeeve [1]

<span>Let the number of nickles be x Let the number of pennies be y Value Value Type Number of of of of EACH ALL coin coins coin coins ------------------------------------------- nickles x $0.05 $0.05x pennies y $0.01 $0.01y ------------------------------------------- TOTALS 56 ----- $1.52 The first equation comes from the second column.</span>

6 0

3 years ago

Read 2 more answers

Ugh I need help I haven’t been doing my work

DaniilM [7]

Answer:

You should do your homework.

Step-by-step explanation: It's not good if you don't do it.

6 0

2 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago

Find the value of the lesser root of x 2-8x+7=0

mariarad [96]

Hi there! The answer is x = 1

${x}^{2} - 8x + 7 = 0$

$(x - 7)(x - 1)$
Rule AB = 0, gives A = 0 or B = 0

$x - 7 = 0 \: \: or \: \: x - 1 = 0 \\ x = 7 \: \: \: \: \: \: \: \: \: or \: \: x = 1$
Therefore, the smallest of both roots is x = 1.

7 0

2 years ago

Solve (9^62773 + 2)^83721

shutvik [7]

Remember the order of operations and do what is in parenthses first.

Take 9 to its power first, then add 2. Once you get that, take that answer to the 83721 power.

I would give you the answer, but my calculator is saying invalid input every time I am trying to use such high exponents. Sorry :( But I hope that this helps

3 0

3 years ago