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Nataly_w [17]
2 years ago
6

Volume of cylinder with a base radius of 5 and height of 3

Mathematics
1 answer:
Anna007 [38]2 years ago
6 0

Answer:

235.5.

Step-by-step explanation:

<u>VOLUME: THE AMOUNT OF SPACE OCCUPIED BY A 3D OBJECT.</u>

The formula for volume of a cylinder is:

pi*r^2*h (3.14 * radius *radius * height)

The radius of this cylinder is 5 and the height is 3.

Now, we can plug the numbers in the formula.

<u>SOLVE:</u>

<u />pi *5^2*3(3.14*5*5*3)=235.5.<u />

The product of the equation is 235.5.

I, therefore, believe the volume of this cylinder is 235.5.

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That question is accompanied by these answer choices:

<span>A. The scale is accurate but not precise.
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3 years ago
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fgiga [73]

Answer:

The piano was in the air for 18.34 seconds.

Step-by-step explanation:

The height of the piano after t seconds is given by the following equation:

f(t) = -16t^{2} + 320t - 256

Initially, the piano is below the ground level. At the first root of the equation, it will go into the air, and then some time after that it will fall down again, which is at the second root of the equation.

Roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

f(t) = -16t^{2} + 320t - 256

So

a = -16, b = 320, c = -256

\bigtriangleup = (320)^{2} - 4*(-16)*(-256) = 86016

t_{1} = \frac{-320 + \sqrt{86016}}{2*(-16)} = 0.8348

t_{2} = \frac{-320 - \sqrt{86016}}{2*(-16)} = 19.17

Subtracting:

19.17 - 0.8348 = 18.34

The piano was in the air for 18.34 seconds.

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Step-by-step explanation:

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