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zysi [14]
3 years ago
10

Anyone please could help

Mathematics
1 answer:
Shalnov [3]3 years ago
5 0
The answer would be c.127
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3 years ago
George cut a cake into eight pieces. Explain what the unit fraction of the cake is.​
morpeh [17]

Answer:

1/8th

Step-by-step explanation: A unit fraction is a rational number written as a fraction where the numerator is one and the denominator is a positive integer. A unit fraction is therefore the reciprocal of a positive integer, 1/n. Examples are 1/1, 1/2, 1/3, 1/4 ,1/5, etc. so in this case the cake is eight slices so 1/8

6 0
3 years ago
Behind my math class help pls
vladimir2022 [97]

Answer:

Please check the explanation.

Step-by-step explanation:

Part a)

Given that the two parallel lines are crossed by a transversal line.

Given that

m∠2 = 2x + 54 and m∠6 = 6x - 11

Angle ∠2 and ∠6 are corresponding angles.

Corresponding angles are congruent.

Thus,

m∠2 = m∠6

2x + 54 = 6x - 11

flipe the equation

6x - 11 = 2x + 54

subtract 2x from both sides

6x - 2x - 11 = 2x - 2x + 54

4x - 11 = 54

adding 11 to both sides

4x - 11 + 11 = 54 + 11

4x = 65

dvide both sides by 4

4x/4 = 65/4

x = 16.2500    (round to 4 decimal places)

Part b)

We have already determined

x = 16.2500

Given

m∠2 = 2x + 54

substitute x = 16.2500 in the euation

        = 2(16.2500) + 54

        = 86.5°

As angle ∠2 and angle ∠1 lie on a straight line. Hence, the sum of their angles must be 180°.

i.e.

m∠1 + m∠2 = 180°

substituting m∠2 =  86.5° in the equation

m∠1 + 86.5°  = 180°

subtracting 86.5° from both sides

m∠1 + 86.5° - 86.5° = 180° - 86.5°

m∠1 = 93.5°

Therefore, the measure of angle m∠1 is:

  • m∠1 = 93.5°
4 0
3 years ago
Help, brainliest to whoever answers
jok3333 [9.3K]
Answer: 45
Plug in 150 for s in the equation and solve
3 0
2 years ago
Read 2 more answers
Write a linear equation that passes through the two points (-6, -7) and (3, -4).
Phantasy [73]

linear equation that passes through the two points (-6, -7) and (3, -4) is y=\frac{1}{3}x-5

Step-by-step explanation:

We need to write the equation that passes through the two points (-6, -7) and (3, -4).

The equation can be written is point slope form.

The standard form of point slope equation is:

y=mx+b

where m is the slope and b is the y-intercept

Finding slope m:

Slope can be found by using formula:

slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=-4,y_{1}=-7,x{2}=3,x_{1}=-6\\slope =\frac{-4-(-7)}{3-(-6)}\\slope=\frac{-4+7}{3+6}\\slope=\frac{3}{9}\\slope=\frac{1}{3}

So, slope is \frac{1}{3}

Now finding y-intercept b

Putting slope \frac{1}{3} and point(-6,-7)

y=mx+b\\x=-6,y=-7,m=\frac{1}{3} \\-7=\frac{1}{3}(-6)+b\\-7=-2+b\\b=-7+2\\b=-5

So, value of b is -5

Putting values to find the equation:

y=mx+b\\m=\frac{1}{3} and b=-5\\y=\frac{1}{3}x-5

So, linear equation that passes through the two points (-6, -7) and (3, -4) is y=\frac{1}{3}x-5

Keywords: Linear Equation,

Learn more about Linear Equation at:

  • brainly.com/question/12954015
  • brainly.com/question/1979240
  • brainly.com/question/2601054

#learnwithBrainly

5 0
3 years ago
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