A rectangle has a length that is 8 inches more than its width, w. The area of the rectangle is 65 square inches.
2 answers:
Answer:13 and 5 are the lengths
Step-by-step explanation: if its 8 inches more on one side than the other then it goes like this 9x1 is 9. 10x2 is 20. 11x3 is 33. 12x4 is 48. 13x5 is 65. 13x5 is the rectangle.
Answer:
13in
Step-by-step explanation:
Let the width be w
The length will be 8+w
(8+w)(w)=65
8w+w^2=65
w^2+8w-65
Use quadratic equation formula.
You will get two answers
w=5 or w= -13
Pick the answer that is more sensible.
It cannot be a negative number; hence use 5in
5in+8in= 13in
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the number less than -1.5 would be 0-1 so it would be A)
We know that <span>The formula for the area of a quadrilateral with perpendicular diagonals is </span>A=(0.5)*(D1*D2) A=58 in² D1=AC=14.5 in D2=BD=? so D2=2*A/D1-----------> 2*58/14.5-----------> D2=8 in BD=D2=8 in the answer is BD=8 in
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