Which of the following is not a function? 3-1 3-2 3-7 7-1 7-2 7-7
1 answer:
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Answer:
0.02651
Step-by-step explanation:
P(all 5 are boys) =
= 0.02651 ( wow low)
Answer: Choice B) (2,0)
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Set the first piece equal to zero and solve for x
x^2 - 4 = 0
x^2 = 4
x = sqrt(4) or x = -sqrt(4)
x = 2 or x = -2
Keep in mind that the first piece y = x^2-4 is only graphed when x = 2 or larger, so we ignore x = -2. This is one x intercept, but there may be more. Let's check the other graph to see what we get.
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Set the second piece equal to zero and solve for x
x-2 = 0
x-2+2 = 0+2
x = 2
We get the same result as above in the prior section. Because of this, the two pieces connect at this junction point.
The x intercept x = 2 leads to the location (2,0). The x intercept always occurs when y = 0.
The graph below shows this.
side note: the red piece y = x^2 - 4 looks linear, but it's actually not a straight line. It's just a really stretched out curve.
Answer:
Step-by-step explanation:
We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).
Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus
Join JH and GI such that they form the diagonals of the quadrilateral.Now,
JH= and
GI=
Now, mid point of JH=
=
Mid point of GI=
Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.
Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.
Thus, From ΔGIJ, we have
(1)
Now, JI= and GJ=
Substituting these values in (1), we get
Thus, GIJ is a right angles triangle.
Hence, GHIJ is a rectangle.
Also, The diagonals GI= and HJ=
are equal, thus, GHIJ is a rectangle.