You have several purchases you

Mathematics

1 answer:

svetlana [45]2 years ago

8 0

The answer: $24.05

How to:
Go through the graph and add all the values together
Then subtract $3.00 from the cost
Then add 4% sales tax

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Help me and I’ll give brainliest! Plsss

olganol [36]

Answer:
(#14 - supplementary) x = 10.5
(#15 - supplementary) x = 10

Explanation:
For these problems, we must know that a supplementary angle can be viewed as a sum of angles that add to 180 degrees. With this known, we can write our equations to find x.

(#14)
15x - 12 + 5x - 18 = 180
20x - 30 = 180
20x = 210
x = 10.5

(#15)
6x + 13 + 14x - 33 = 180
20x - 20 = 180
20x = 200
x = 10

Hope this helps.

Cheers.

4 0

1 year ago

Determine if the set is a Pythagorean triple

balandron [24]

Answer:

Pythagorean Triples are sets of whole numbers for which the Pythagorean Theorem holds true. The most well-known triple is 3, 4, 5. This means that 3 and 4 are the lengths of the legs and 5 is the hypotenuse.

4 0

2 years ago

on Monday Jimmy went to see a movie that was 112 minutes long jimmy was late and missed first 12 minutes of the movie what fract

fgiga [73]

Answer:

100 / 112

Step-by-step explanation:

100 miniuts is a part of 112 adn is not a fraction and it does not say to siplify so you should be good.

6 0

2 years ago

A camera has a listed price of $594.99 before tax. If the sales tax rate is 7.25% , find the total cost of the camera with sales

Zarrin [17]

Answer:

$638.16

Step-by-step explanation:

594.99x7.25%=43.17

594.99+43.17=638.18

5 0

2 years ago

Find the multiplicative inverse of 6 + 2i

Marina CMI [18]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2774989

________________

Find the multiplicative inverse of

$\mathsf{z=6+2i}$

________

The inverse multiplicative of $\mathsf{z=a+bi}$ is

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\
=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}$

$=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\
\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}$

________

For this question,

$\mathsf{z=6+2i}$

So,

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{6+2i}}\\\\\\
=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\
=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\
=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}$

$\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

6 0

2 years ago

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