Uniform distribution between 0 and 7 minutes.
Need to know probability of waiting greater than 3.25 minutes.
P(T>3.25) = (7-3.25)/(7-0) = 0.536
Answer: the probability that waiting time exceeds 3.25 minutes is 0.536
Answer:
(3,0)
Step-by-step explanation:
0(x)+3=3
6(y)-6=0
5/6=1/3+(3/6). 3/6 is the correct answer
F<span>(x)</span>=<span>cos<span>(x)</span></span>⋅<span>sin<span>(x)</span></span>
is an odd function
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