All of these percentages will be from fractions out of 2,175.
Winter: 234/2175 = 10.8%
Spring: 673/2175 = 30.9%
Summer: 843/2175 = 38.8%
Fall: 425/2175 = 19.5%
Answer:
p (X= 4) = 0.266
Explanation:
Probability of randomly selected baby elk to survive adulthood = 46%
As per binomial setting
p (X= k) = 
Substituting the given values, we get -
p (X= 4) = 
p (X= 4) = 
p (X= 4) = 0.266
The sampling distribution of the sample means for the random sample of 100 dogs will be 0.25.
<h3>How to compute the sample mean?</h3>
From the given information, the population distribution of the QDA scores for the fur of dogs is roughly uniform with mean 5.4 and standard deviation is 2.5.
In this case, the sampling distribution of the sample means will be:
= ✓SD/n
= ✓(2.5)²/100
= ✓0.0625
= 0.25
In conclusion, the correct option is 0.25.
Learn more about sampling on:
brainly.com/question/24466382
Most colleges require 2 or 3 letter of reccomendsations so b
