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Brrunno [24]
3 years ago
6

What is the missing number in the synthetic division problem below?

Mathematics
1 answer:
Crank3 years ago
6 0

Given:

A synthetic division problem.

To find:

The missing number it in the given synthetic division problem.

Solution:

The given synthetic division problem is:

3|\overline{3\quad -2\quad 2\quad 4}\\

           \quad 6\quad 8\quad 20\\

     \overline{3\quad 4\quad ?\quad 24}

In synthetic division, we need to add first and second row to get the bottom row.

3+0=3

-2+6=4

4+20=24

Similarly,

2+8=10

Therefore, the missing value in the given synthetic problem is 10. Hence, the correct option is C.

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What is the answer = 8w- 8 - 6w = 4w - 7<br> w= ??
ololo11 [35]

Answer:

<em>- 1/2     (or - 0.5) </em>

Step-by-step explanation:

so first, simplify by combining like terms.

so 8w-6w = 2w

so now we have

2w - 8 = 4w - 7

now we have to get the w's to one side of the equation so we can solve for it. so that mean we have to subtract 2w from both sides. 2w - 2w is 0. and then 4w - 2w = 2w. so now we have

-8 = 2w - 7

then to slowly start isolating w, add 7 to both sides of th equation. so now its

-1 = 2w

finally to get w by itself divide 2 from both sides.

and the answer is

-\frac{1}{2} = w

5 0
2 years ago
I need help with question 2 !!
Stells [14]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Answer the question pls xx
yKpoI14uk [10]

Answer:

3 lines of symmetry

Step-by-step explanation:

the lines go through the vertices of the triangle

3 0
2 years ago
Determine if the sequence is arithmetic. If it is, find the term named in the problem.
Brums [2.3K]

Answer:

a_{39} <em>= 279</em>

Step-by-step explanation:

a_{n} = a_{1} + (n - 1)d

d = a_{2} - a_{1}

~~~~~~~~~

d = - 17 + 25 = - 9 + 17 = - 1 + 9 = 8

a_{39} = - 25 + 8(39 - 1) = 279

a_{39} <em>= 279</em><em> </em>

5 0
3 years ago
Solve the Quadratics:
klasskru [66]

Answer:

Step-by-step explanation:

1 ) k²-8k = 0

k(k-8)=0

k = 0 or k=8

2) a²+5a=0

a(a+5) = 0

a=0 or a  = - 5

3 ) 6n²+5n-25=0

delta = b²-4ac      b =5 and a = 6   and   c= - 25

delta = 5²-4(6)(-25) = 625 = 25²

n 1 = (-5+25)/12 = 20/12 = 5/3

n 2 = (-5-25)/12 = -  30/12  = -5/2

same method for 4) and 5)

6 0
3 years ago
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