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2 years ago

Identify the center and radius for the equation x ^ 2 + (y - 3) ^ 2 = 4

Mathematics

1 answer:

marissa [1.9K]2 years ago

6 0

Answer:

r = 2. The center is at (0, 3).

Step-by-step explanation:

Compare the given x ^ 2 + (y - 3) ^ 2 = 4 to the standard equation

(x - h)^2 + (y - k)^2 = r^2.

It becomes obvious that h = 0, k = 3 and r = 2. The center is at (0, 3).

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