How are nucleic acids and proteins similar?

When an ionic solid is added into a solvent, you can see that the ionic solid dissociates into its respective cations and anions

joja [24]

Answer: See explanation

Explanation:

Based on the information given in the question, the ranking from the first step to the last step goes as follows:

1. Dissolution of salt into cations and anions

2. Hydration of anions

3. Hydration of cations

4. Dissolved cations and anions begin to deposit as a solid salt.

5. Rate of dissolution is equal to the rate of recrystallization.

4 0

3 years ago

100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are $0.38\times 10^{-5}$ and $18.62\times 10^{-5}g$ respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

$3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}$

$n=0.38\times 10^{-5}$

n = moles of $NaCN$ = $\frac{\text {given mass}}{\text {Molar mass}}$

$0.38\times 10^{-5}=\frac{x}{49g/mol}$

$x=18.62\times 10^{-5}g$

Thus the number of moles and the mass of the solute are $0.38\times 10^{-5}$ and $18.62\times 10^{-5}g$ respectively

6 0

3 years ago

Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.

Klio2033 [76]

Explanation:

to calculate theoratical yield...first we must calculate how much Sucrose moles we have..in order to to do so...we must calculate molar mass of sucrose.

molar mass of sucrose is 342.3 g/mol.

now we can calculate how many sucrose moles we have by dividing the mass with molar mass of sucrose

735g/(342.3g/mol)=2.147mol

theoratically...according to stoichiometry..every 1 mole of sucrose yields 4 moles of ethanol...so...

2.147mole yield 2.147*4mol=8.588mol

now we must calculate weight of that much ethanol..molar mass of ethanol is 46.07 g/mol...

so we can multiple moles by molar mass to obtain the weight 8.588mol*46.07g/mol=395.649g

but we only obtained 310.5g...so percentage we have is

$\frac{310.5}{395.649} \times 100$

78.47%

if there is trouble with molar mases I used....use what you calculated...

If my explanation is good enough...please mark it as brainliest.thanks

5 0

3 years ago

I have 26 protons,26 electrons, and 30 neutrons?

Amiraneli [1.4K]

Answer:

Iron (Fe)

Explanation:

# of protons is the atomic number of the element

the element with the atomic number 26 is Iron

with 26 electrons this means it is Iron with no charge

with 30 neutrons this means the atomic weight will be

26 (protons) + 30 (neutrons) = 56

the real atomic weight of iron listed on the periodic table is 55.845, this rounded up is 56.

7 0

3 years ago

Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine

dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

pKb1 = - log [kb]

5.1 = - log [kb]

take Antilog of both side

[kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

From the question, 1900 ml of solution contains 1 g of Q

Therefore, 1000 ml of solution will contain........... x g of Q

x = 1000 /1900

x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

= 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

At Equilibrium, Kb = x² / 0.0016

7.94 x 10∧-6 = x² / 0.0016

x = √ 0.0016 × 7.94 x 10∧-6

x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4: Calculating the pH of Quinine

Recall, pOH = - log [OH-]

pOH = - log [1. 127 × 10∧-4]

pOH = 3.948

Also recall that pH + pOH = 14

pH = 14 - 3.948

pH = 10.05

8 0

4 years ago