Ask question

Ask question

All categories

Svetllana [295]

3 years ago

9

I need help ASAP please and thank you

1 answer:

Over [174]3 years ago

7 0

Answer:

"a" is the answer because 3x+2 can not be equal to zero

Step-by-step explanation:

You might be interested in

The product of 45/87 and --9/10 is

grandymaker [24]

Answer:

0.4655172413793

Step-by-step explanation:

45/87 ×-9/10 i

405÷870

0.4655172413793

7 0

3 years ago

The height of a painting is twice its width. You want a 4 inch wooden frame for the painting. Write a variable expression for th

vfiekz [6]

Answer:

hx2+4

Step-by-step explanation:

Just doubled the painting width and you get your height.

8 0

3 years ago

-9(-5k + 3m) + 9m -5(-5m + 9k)

Kisachek [45]

7m -36k
Here’s the answers

8 0

3 years ago

Read 2 more answers

The original box of cereal had 16 grams of sugar per serving. The new box of cereal has 25% less sugar. How many grams of sugar

Leno4ka [110]

12 grams.
If it’s 25% less, that’s the same as 1/4 less.
3/4 of 16 is 12.

6 0

3 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago