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mihalych1998 [28]
3 years ago
5

An online video streaming service offers two plans for unlimited streaming. Plan A has a one-time $25 membership fee and is $8 p

er month. Plan B has a $5 membership fee and is $12 per month.
Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

so,what is the questions?

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What is f(-8) for the function f?<br> F= 11(x-24)/2
mojhsa [17]

Answer:

-176.........................

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If every positive number has two square roots and you can find of the side of a square window by finding a square root of the ar
butalik [34]
Every positive number has two square roots - a positive and a negative (unless the value is 0).
The length of something can only be a positive number and since there is only one positive square root, there is only one answer.
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3 years ago
A circle has an area of 153.86 units2 and a circumference of 43.96 units. If the radius is 7 units, what can be said about the r
dusya [7]

Step-by-step explanation:

\text{Circumference:}\\\\C=2\pi r\\\\\text{Area:}\\\\A=\pi r^2\\\\\dfrac{A}{C}=\dfrac{\pi r^2}{2\pi r}\qquad\text{cancel}\ \pi\ \text{and}\ r\\\\\dfrac{A}{C}=\dfrac{r}{2}\\\\\bold{The\ number\ of\ areas\ of\ a\ circle\ is}\ \dfrac{r}{2}\ \bold{larger\ than\ its\ circumference}.

\text{For a given area and circumference}:\\\\A=153.86,\ C=43.96,\ r=7\\\\\dfrac{A}{C}=\dfrac{153.86}{43.96}=3.5=\dfrac{7}{2}=\dfrac{r}{2}\\\\\dfrac{A}{C}=\dfrac{r}{2}

4 0
3 years ago
Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.
34kurt

Answer:

  • Infinitely many solutions

Step-by-step explanation:

First, let's organize the equations of the lines into slope-intercept form.

  • x + 4y = 1
  • => 4y = -x + 1
  • => y = -x/4 + 1/4

And,

  • 2x + 8y = 2
  • => 8y = -2x + 2
  • => y = -2x/8 + 2/8
  • => y = -x/4 + 1/4

Since both the graphs are the same, the two equations have infinitely many solutions.

5 0
2 years ago
93 times 10 to the sixth power
Varvara68 [4.7K]
93 x 10^6 =
93 x 1,000,000 = 93,000,000
6 0
3 years ago
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