WHOEVER ANSWERS FIRST GETS BRAINLIEST AND ILL GIVE YOU MONEY IN PAAAYYPALPLLLEEWSSE HELPCMETHIS IS FIR A TEST AND EXPLAIN

Susie wants to buy a snowboard that cost $530. She has already saved $98 for it. She makes $72 a week babysitting. Which inequal

Alex777 [14]

Its B , 6 because if you subtract 98 from 530 you get 432 and if you divide that by 72 you get 6 :)

6 0

4 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

so

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

so

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago

Solve the equation. Explain each step and identify the property used to reach each step.

Tom [10]

To isolate x, we will first subtract 0.8 from both sides.

0.6x + 0.8 = 1.4

-0.8 -0.8

0.6x = 0.6

Now all we have to do is divide both sides by 0.6, because it is the number besides x.

0.6x/0.6 = 0.6/0.6

x = 1

So you get the answer of x = 1.

7 0

3 years ago

A vehicle purchased for $ 27500 depreciates at a constant rate of 4 % . Determine the approximate value of the vehicle 12 years

Anna35 [415]

Answer:

$13,200

Step-by-step explanation:

Multiply the original cost by .04 and 12 years

(original cost)(rate in decimal form)(time)

6 0

4 years ago

What is the function rule for the following situation? Rex paid $20 for a membership to the pool and pays $300 each time he goes

asambeis [7]

f(x)=20+300x

Also, Rex should find a different pool because that fee is ridiculous.

8 0

3 years ago