C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
Answer:
Since I cant say which answer due to no graph, I'll tell you How to do so.
Step-by-step explanation:
if it is A, then the there is at least one angle or line length that is not the same. To find the area of a grided shape, use the traingle theorm of a^2+b^2=c^2.
if it is B, that meants moving the shape to the other will result in a perfect fit. Be sure to find if all side lengths are the same as that means that the shape IS congrouent, as equal side length means equal angles. However, it will not be this choice if the shape is mirrored to the other
A rotation and tranlastion means it is flipped either upside down or up and moved to the shape.
D, a reflection, which means its the opposite. Like a mirrored shape. Then you move it.
C is on the line and D is not on the line.
-1/2(-40)+1=21
-1/2(20)+1≠-11
I will check for the answer on that gimme a min
<h3>
Answer:</h3>
∠BDC and ∠AED are right angles
<h3>
Step-by-step explanation:</h3>
Because ∠C ≅ ∠C, the additional bit of information above can be used to show AA similarity.
____
None of the other offered choices says anything about <em>both</em> triangles. In order to show similarity, you need information about corresponding parts of the <em>two</em> triangles. Information about one triangle alone is not sufficient.
