5th grade math. correct answer will be marked brainliest.
1 answer:
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Answer:
see explanation
Step-by-step explanation:
Part 1
The n th term of a geometric sequence is
= a
where a is the first term and r the common ratio
Given = 128, then
a = 128, that is
32a = 128 ( divide both sides by 32 )
a = 4 ← first term
Part 2
= 4
= 4 × 1048576 = 4194304
Answer:
hello your question is incomplete below is the missing parts
(a) A\ (A\B) = B\(B\A)
(b) A\ (BA) = B\(A\B)
answer : A\ (A\B) = B\(B\A) = always true
A\ (BA) = B\(A\B) = sometimes true and sometimes false
Step-by-step explanation:
(a) A\ (A\B) = B\(B\A). = ALWAYS TRUE
using de Morgan's law to prove this
A\ (A\B) = A\ ( A ∩ B^c )
= A ∩ ( A^C ∪ B )
= ( A ∩ A^C ) ∪ ( A ∩ B )
= Ф ∪ ( A ∩ B )
= ( A ∩ B )
ALSO : B\(B\A) = attached below is the remaining parts of the solution
B) A\ (BA) = B\(A\B) = Sometimes true and sometimes false
attached below is the prove using De Morgan's law
