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tekilochka [14]
3 years ago
10

Which number has an absolute value that is less than 25?

Mathematics
1 answer:
Minchanka [31]3 years ago
3 0
-24 through 24, absolute value is how far a number is from 0
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What is the length of a segment in the complex plane with endpoints at 4 + 2i and 7 – 2i?
ira [324]

Answer:

5

Step-by-step explanation:

The complex number 4 + 2i on the complex plane has coordinates (4,2) and the complex number 7 - 2i has coordinates (7,-2). Thus, the length of a segment in the complex plane with endpoints at 4 + 2i and 7 – 2i is

\sqrt{(4-7)^2+(2-(-2))^2}=\sqrt{(-3)^2+4^2}=\sqrt{9+16}=\sqrt{25}=5.

6 0
3 years ago
Read 2 more answers
Simplify 24 − (23 + 22).<br> HELP FAST
RSB [31]

Answer:-21

Step-by-step explanation:

23+22=45

45-24=21

then flip 24 and 45 to get negative

8 0
3 years ago
Read 2 more answers
PLS I WILL GIVE BRAINLIEST
Nana76 [90]

Answer:

208 cm^2

Step-by-step explanation:

We can find the area of the net by adding up the area of each of the 6 rectangles that make up the net. Since two of each rectangle are the same, we only have to find the area of the 3 different sized rectangles and multiply each by 2.

Rectangle pairs are:

  • Left rectangle and right rectangle
  • Top rectangle and the rectangle above the bottom rectangle
  • Bottom rectangle and the rectangle surrounded by all for sides

Now, let's solve the question.

Left rectangle:

6 x 4 = 24, rectangle has area of 24 squared cm

Top rectangle:

6 x 8 = 48, rectangle has area of 48 squared cm

Bottom rectangle:

4 x 8 = 32, rectangle has area of 32 squared cm

Add up the areas:

(24 x 2) + (48 x 2) + (32 x 2) = 208

The rectangle has a surface area of 208 squared cm

4 0
3 years ago
Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f
prisoha [69]

Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, (x_1,y_1) and (x_2,y_2), is given by:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}

DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}

NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4

<u>Two edges of the same length</u>, hence, it is an isosceles triangle, given by option b.

You can learn more about distance between two points at brainly.com/question/18345417

6 0
2 years ago
I need to know How to solve it
dezoksy [38]
SohCahToa
Heard of it?
Sine- opposite over hypotenuse 
Cosine-adjacent over hypotenuse 
Tangent- opposite over adjacent 
4 0
3 years ago
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