Answer:
<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.
Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:
n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).
So, n can be written as 3 times another integer, thus n is divisible by 3.
<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.
Assume that n is divisible by 3. The above proof suggest that we write it as
n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).
As k, k+1, k+2 are three consecutive integers, we have completed our goal.
Step-by-step explanation:
4(c-6)
distribute 4(c-6)
4xc and -6x4
youll get 4c-24
Answer:
84/90
Step-by-step explanation:
Let 0.9333....... be x.
10x = 9.3333....... & 100x = 93.33333.......
So,
=> 100x - 10x = 93.33333...... - 9.333333.....
=> 90x = 84
=> x = 84/90
72/96 * 100= 75% so the answer is 75%
Answer:
three u's and an I
Step-by-step explanation:
3×3=9
that's 3 u's so if you add an I its 10
