Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
Answer:
8xyz
Step-by-step explanation:
multiply all numbers and alphabets
- 288xyz, 2.360xyz, 3.648xyz
- find HCF of numbers and after multiply by xyz
- 288={2×2×2×31}
- 360={2×2×2×3×3×5}
- 648={2×2×2×3×3×3×3}
- HCF={2×2×2}xyz
- 8xyz
The rule is "whatever the input is, multiply it by 5, then subtract 2"
For example, if the input is 4 then 4*5 = 20 and 20-2 = 18
So in short, the input 4 leads to the output 18 as shown in the top row of the diagram.
The answer is the box on the bottom row, right hand side where it says "x 5" and "-2" in the two bubbles.
Answer:
$111400
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 5.7%/100 = 0.057 per year,
then, solving our equation
I = 100000 × 0.057 × 2 = 11400
I = $ 11,400.00
The simple interest accumulated
on a principal of $ 100,000.00
at a rate of 5.7% per year
for 2 years is $ 11,400.00.
