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3 years ago

Which equation is NOT a linear function?

Mathematics

2 answers:

Anni [7]3 years ago

4 0

Y=x^2-2

i got this one right

Paul [167]3 years ago

3 0

Answer:

$y = {x}^{2} - 2$

Step-by-step explanation:

because it's has two zeroes

hence it is known as the quadratic function

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Which equation represents the data shown in the table below?

gayaneshka [121]

I can’t really read this but I think it’s b

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3 years ago

I am confusion. help me

timofeeve [1]

Multiple the two Collins

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3 years ago

There are three consecutive integers, such that six times the first, minus two times the second, equals the third integer plus f

frozen [14]

Answer:

Step-by-step explanation:

Given that:

Integers : x, x + 1, x + 2

6x - 2(x + 1) = (x+2) + 5

6x - 2x - 2 = x + 2 + 5

4x - 2 = x + 7

4x - x = 7 + 2

3x = 9

x = 9/3

x = 3

First integer = x = 3

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2 years ago

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$