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Shkiper50 [21]
3 years ago
15

Given b(x) - 1X+4. what is b(-10)? -10 -6 6 14

Mathematics
2 answers:
Lostsunrise [7]3 years ago
6 0
The answer is -6 you welcome :)
liraira [26]3 years ago
5 0

Answer:

D. 1×10⁻⁸ M

Explanation:

[H⁺] [OH⁻] = 10⁻¹⁴

(1×10⁻⁶) [OH⁻] = 10⁻¹⁴

[OH⁻] = 1×10⁻⁸

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—бу – 3 = 3 – бу<br><br> No solution <br> All real numbers <br> I need the answer quickly!!
topjm [15]

Answer:

no solutions

Step-by-step explanation:

-6y-3=3-6y

1. add 6y to both sides:

-6y-3 +6y=3-6y +6y

-3=3

since -3 doesn't equal 3, there are no solutions.

5 0
3 years ago
What is the relationship between 7 and —7?
Alex73 [517]

Answer: absolute value

Step-by-step explanation:

Sorry for my writing it’s horrible ik I’m in a hurry rn lol

4 0
3 years ago
Which shows another way to write 9.54?
Lelu [443]

Answer:

It would be C

Step-by-step explanation:

3 0
3 years ago
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
3 years ago
PLEAse i need help brainlist if u get it right
Naya [18.7K]

Answer:

C) The resulting figure will be congruent to the original rectangle, because dilations with a scale factor of 1 have the same coordinates.

Step-by-step explanation: Multiplying any number by 1 will result in the same number, this applies to coordinates as well.  

7 0
3 years ago
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