Answer is last one. last one is false
Every real number is a rational number
example:
square root (3) is real number
but square root (3) is not a rational number
hope it helps
By letting
we get derivatives
a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to
Examine the lowest degree term , which gives rise to the indicial equation,
with roots at r = 0 and r = 4/5.
b) The recurrence for the coefficients is
so that with r = 4/5, the coefficients are governed by
c) Starting with , we find
so that the first three terms of the solution are
Answer:
2
Step-by-step explanation:
Answer:
• x = -4, x = 0, x = 1
Step-by-step explanation:
x is a factor of all terms, so x=0 is a zero. (Eliminates choices 1 and 5.)
The sum of coefficients is 0, so x=1 is a zero. (Eliminates choices 3 and 4.)
Reversing the sign of the odd-degree terms gives signs of -++, so there is one sign change, hence one negative real root (by Descartes' rule of signs). This confirms choice 2 as the answer.
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Of course, your graphing calculator can answer this almost as quickly.