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Vladimir79 [104]

3 years ago

9

You found a pair of shoes that cost $80. The store has them on sale for 30% off. How much will you pay for the shoes after the d

iscount?

1 answer:

GREYUIT [131]3 years ago

5 0

Answer:

You will pay 24 dollars for the shoes after the discount.

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marsha waide borrows 5,000 and agrees to pay it back in 2 years . if the simple interst rate is 13% ,find the total amount she p

Dmitry_Shevchenko [17]

Answer:

You want to calculate the interest on $5000 at 13% interest per year after 2 year(s).

The formula we'll use for this is the simple interest formula.

Where:

P is the principal amount, $5000.00.

r is the interest rate, 13% per year, or in decimal form, 13/100=0.13.

t is the time involved, 2....year(s) time periods.

So, t is 2....year time periods.

To find the simple interest, we multiply 5000 × 0.13 × 2 to get that:

The interest is: $1300.00

Usually now, the interest is added onto the principal to figure some new amount after 2 year(s),

or 5000.00 + 1300.00 = 6300.00. For example:

If you borrowed the $5000.00, you would now owe $6300.00

8 0

3 years ago

The lassos high school senior class raised funds for an end of the year cruise getaway. The city gave them a special package for

kirill115 [55]

Answer:

Step-by-step explanation:

x = total number of students

1500 + 367x = 16,600

367x = 16,600 - 1500

367x = 15100

x = 15100 / 367

x = 41.14.......rounds to 41 students <==

this only works if the port fees and taxes that the city gave them are included in the money the class raised

5 0

3 years ago

Morgan has an investment worth $177,500. If his original investment was $50,000 and he received a 15% interest rate, how many ye

Illusion [34]

<h3>Morgan invested for 17 years</h3>

<em><u>Solution:</u></em>

From given,

Principal = $ 50, 000

Total amount = $ 177, 500

Rate of interest = 15 %

Number of years = ?

Interest amount = Total amount - principal

Interest amount = 177, 500 - 50, 000

Interest amount = 127500

<em><u>Use the formula,</u></em>

$Interest = \frac{p \times n \times r}{100}\\\\127500 = \frac{ 50000 \times n \times 15}{100}\\\\127500 = 500 \times 15 \times n\\\\75n = 1275\\\\n = 17$

Thus he invested for 17 years

8 0

3 years ago

Solve (t - 3)2 = 6. The arrow is at a height of 48 ft after approximately _ s<br>and after _s

Slav-nsk [51]

Answer:

The arrow is at a height of 48 ft after approximately <u>0.55</u> s and after <u>5.45</u> s

Step-by-step explanation:

The following information is missing:

<em>The height of an arrow shot upward can be given by the formula s = v0*t - 16*t², where v0 is the initial velocity and t is time.How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? </em>

If the arrow is at a height of 48 ft and its initial velocity is 96 ft/s, then:

48 = 96*t - 16*t²

16*t² - 96*t + 48 = 0

16*(t² - 6*t + 3) = 0

t² - 6*t + 3 = 0

t² - 6*t + 3 + 6 = 0 + 6

t² - 6*t + 9 = 6

(t - 3)² = 6

t - 3 = √6

t - 3 = 2.45; t = 2.45 + 3; t = 5.45

or

t - 3 = -2.45; t = -2.45 + 3; t = 0.55

3 0

3 years ago

Read 2 more answers

One thousand independent rolls of a fair die will be made. Compute an approximation to the probability that the number 6 will ap

pashok25 [27]

Answer:

0.19

Step-by-step explanation:

We are given that

Number of rolls of die=n=1000

Let the event of six coming up be success.Then, in each trial , the probability of success =p=P(success)=P(6)= $\frac{1}{6}$

Let X be the random variable for the number of sixes in the 1000 rolls of die.

Then, $X\sim Binom(1000,\frac{1}{6})$

Since, n is very large,the binomial random variable can be approximated as normal random variable.

Mean, $\mu=np=1000\times \frac{1}{6}=166.67$

Variance= $\sigma^2=np(1-p)=1000\times \farc{1}{6}\times (1-\frac{1}{6})=1000\times \frac{5}{36}=138.89$

$X\sim N(166.67,138.89)$

$P(150\leq X\leq 200)=P[\frac{150-166.67}{11.79}\leq \frac{X-\mu}{\sigma}\leq \frac{200-166.67}{11.79}]$

= $P[-1.41\leq Z\leq 2.83]=P[Z\leq 2.83]-P[Z$

= $\phi(2.83)-\phi(-1.41)$

=0.9977-0.0793=0.9184

Thus, the probability that the number 6 appears between 150 to 200 times=0.92

Now, given that 6 appears exactly 200 times .

Therefore, other number appear in other 800 rolls .

We have to find the probability that the number 5 will appear less than 150 times.

Therefore, for 800 rolls, let the event of 5 coming up be success.

Then , p=P(success)=P(5)= $\frac{1}{5}$

Let Y be the random variable denoting the number of times 5 coming up in 800 rolls.

Then, $Y\sim bin(800,\frac{1}{5})$

Mean, $\mu=np=800\times \frac{1}{5}=160$

Variance, $\sigma^2=np(1-p)=800\times \frac{1}{5}(1-\frac{1}{5})=128$

$Y\sim N(160,128)$ because n is large

$P(Y$

$P(Y$

Hence, the probability that the number 5 will appear less than 150 times given that 6 appeared exactly 200 times=0.19

4 0

3 years ago