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Burka [1]
3 years ago
10

Please answer this correctly without making mistakes

Mathematics
2 answers:
Len [333]3 years ago
6 0

Answer:

The 2-yard pièce of cotton cloth for $13.26

Step-by-step explanation:

2 yards is 6 feet then it would be $2.21 per foot.

The 17 foot piece would cost $3.29 per foot.

sp2606 [1]3 years ago
3 0

To answer this question, you need to determine which one has a lower price per unit.  In this scenario, you must divide the price of the cloths by their length in feet.

For the 2-yard piece of cotton cloth, first convert the length to feet.  There are three feet in a yard, so the cloth is 6 feet.  Then divide:

13.26/6=2.21

For the 17-foot piece of cotton cloth, simply divide:

55.93/17=3.29

The 2-yard piece of cotton cloth for $13.26 is the better buy because it has a lower unit price.

Hope this helps!!

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A whale weighs 4 tons. A great white shark weighs 10,200 pounds. How many
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Step-by-step explanation:

So you have to remember first that one ton is equal to 2,000 pounds. Then, we convert tons to pounds (for the whale) to get 4(2,000)=8,000 pounds. So, the whale weighs 8,000 pounds. The shark weighs 10,200 pounds, so all you have to do now is do 10,200-8,000 to get 2,200 pounds.  So, the answer is C.

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Answer:

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\displaystyle\frac{19\pi}{6}

Step-by-step explanation:

See the graph of the region attached.

To find the intersection between the line and the parabola we set the equation equal to each other, and solve that quadratic equation by factorization:

x^2=9-8x\\x^2+8x-9=0\\(x+9)(x-1)=0\\x=-9,x=1

Since the region is the one for x\ge 0 then the intersection we are interested on is x=1 as it can also be seen in the graph.

Then we set the integral using shell method for revolving about the y-axis:

\displaystyle\int_a^b 2\pi\,x\,h(x)\,dx

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so 8x-9-x^2 (since the line is on the top we subtract from it the parabola)

Then the integral becomes:

\displaystyle\int_0^1 2\pi\,x\,(8x-9-x^2)\,dx

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

Now, solving the integral:

Start by factoring the 2\pi and distributing the x:

=\displaystyle2\pi \int_0^19x-8x^2-x^3dx

Then use the basic rule to integrate:

=\displaystyle2\pi \left[\frac{9x^2}{2}-\frac{8x^2}{3}-\frac{x^4}{4}\right|_0^1

Then evaluate the antiderivative in the limits and subtract:

=\displaystyle2\pi\left[\frac{9}{2}-\frac{8}{3}-\frac{1}{4}-0\right]=\frac{19\pi}{6}

So the volume of the solid is \displaystyle\frac{19\pi}{6}

4 0
3 years ago
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