Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find y.
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Answer:
Step-by-step explanation:
x - 2y = 8
Write this in y = mx +b form
- 2y = -x + 8
Divide the equation by (-2)
Slope = 1/2
The slope of the perpendicular line = -1/m
m = -2 , ( -2 , 5)
Equation: y = mx +b
Plug in m = -2 ,x = -2 and y =5
5 = (-2)*(-2) + b
5 = 4 + b
5 - 4 = b
b = 1
Equation of the line:
y = mx +b
y = -2x + 1