Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find y.
1 answer:
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Answer:
B. 6
Step-by-step explanation:
The diagonals of a parallelogram intersect at their midpoints, so ...
DE = BE
4y -8 = y +10
3y = 18 . . . . . . . add 8-y
y = 6 . . . . . . . . divide by 3
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<em>Additional comment</em>
The value of x is found the same way:
2x = x+2 ⇒ x = 2
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