3 years ago

Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find y.

Mathematics

1 answer:

hodyreva [135]3 years ago

3 0

9514 1404 393

Answer:

B. 6

Step-by-step explanation:

The diagonals of a parallelogram intersect at their midpoints, so ...

DE = BE

4y -8 = y +10

3y = 18 . . . . . . . add 8-y

y = 6 . . . . . . . . divide by 3

<em>Additional comment</em>

The value of x is found the same way:

2x = x+2 ⇒ x = 2

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