Answer:
They are equidistant from origin.
Step-by-step explanation:
Rectangle LMNO is rotated 90° clockwise around the origin to create rectangle L'M'N'O'. Which statement would best describe the relationship between points N and N'?
They are equidistant from origin.
They are midpoints of segment ON and segment O prime N prime.
They are equidistant from point O.
They are midpoints of segment LN and segment L prime N prime.
Answer: If a point with location N(x, y) is rotated 90° clockwise around the origin, the new coordinate N' is at (y, -x). The distance of the two points from the origin O(0, 0) can be calculated using:
Therefore ON = ON'. The points N and N'are equidistant from the orign
Answer:
The distance is:
Step-by-step explanation:
We re-write the equation of the line in the format:
Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.
In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:
Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:
We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:
Then we solve that equation for t, to get:
Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:
Then to find the distance we just use the distance formula:
So we get:
Answer:
Algebra archive containing a full list of algebra questions and answers from October ... Given the sample space, S = {2,5,7,10), determine the answers to the ... +5x2-4x-20 x2+3x Points out of 8.75 Select one: P Flag question a. ... + 5 t(x)=x -2 Write the expressions for (s•t)(x) and (s + t)(x) and evaluate (s - t)(-1). (sºt)(x) = 0 (s.
Step-by-step explanation:
sorry po kung mali :-(
Commutative Property allows 5=b to be written as b=5!
I hope this helped! Mark me Brainliest! :) -Raven❤️
It takes two steps to solve an equation or inequality that has more than one operation:<span>Simplify using the inverse of addition or subtraction.<span>Simplify further by using the inverse of multiplication or division.
</span>5-5x=0
5-5x-5=0-5
-5x=-5
-5x/-5=-5/-5
x=1</span>
