They are similar. Both isosceles triangles
Answer:
A
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k) = (- 2, 3) and r = 3 , then
(x + 2)² + (y - 3)² = 9 ← expand left side using FOIL
x² + 4x + 4 + y² - 6y + 9 = 9 ( subtract 9 from both sides )
x² + y² + 4x - 6y + 4 = 0 → A
1. x = -4 ; f(x) = -(-4) = 4
2. x = -3 ; f(x) = 2(-3) + 1 = -5
3. x = 0 ; f(x) = 2(0) + 1 = 1
4. x = 2 ; f(x) = 2 + 3 = 5
5. x = 5 ; f(x) = 5 + 3 = 8
Y - y₁ = m(x - x₁)
y - 2 = 4(x - 7)
y - 2 = 4(x) - 4(7)
y - 2 = 4x - 28
+ 2 + 2
y = 4x - 26
Answer:
System of linear equations
![\left\{\begin{matrix} 3a+c=38 \\\\ 3a+2c=52 \end{matrix}\right.](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Bmatrix%7D%203a%2Bc%3D38%20%5C%5C%5C%5C%20%20%203a%2B2c%3D52%20%5Cend%7Bmatrix%7D%5Cright.)
a: adult ticket price and c: child ticket price
Step-by-step explanation:
This system of equations can be used to find the price of the adult and child tickets.
We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).
Let a: adult ticket price and c: child ticket price,
we have for the first day that 3 adult tickets and 1 child ticket adds $38:
![3a+1c=38](https://tex.z-dn.net/?f=3a%2B1c%3D38)
and for the second day we have that 2 adult tickets and 2 child tickets adds $52:
![3a+2c=52](https://tex.z-dn.net/?f=3a%2B2c%3D52)
If we write this as a system of equations, we have:
![\left\{\begin{matrix} 3a+c=38 \\\\ 3a+2c=52 \end{matrix}\right.](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Bmatrix%7D%203a%2Bc%3D38%20%5C%5C%5C%5C%20%20%203a%2B2c%3D52%20%5Cend%7Bmatrix%7D%5Cright.)