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notsponge [240]
3 years ago
9

Find x if f(x) = 2x + 7 and f(x) = -1.

Mathematics
2 answers:
damaskus [11]3 years ago
7 0
The answer is positive 5
skelet666 [1.2K]3 years ago
5 0

Answer:

x=-4

Step-by-step explanation:

We are given the function:

f(x)=2x+7

And we want to find <em>x</em> when f(<em>x</em>) = -1.

Substitute:

-1=2x+7

Subtract seven from both sides:

2x=-8

Divide both sides by two. Hence:

x=-4

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Answer:

96

Step-by-step explanation:

6+6=12

12+12=24

24+24=48

and

48+48=96

8 0
3 years ago
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Which of the following is equivalent to (n-3)(n-5) a. n2-8n+15, b. n2+8n-15, c. n2-15n+8
solong [7]
Foil the binomials

First: n*n=n^2
Outer: n*-5=-5n
Inner: -3*n=-3n
Last: -3*-5=15

Put it together and simplify
n^2-5n-3n+15
n^2-8n+15

Final answer: A
5 0
3 years ago
Help me with this geometey question !! thanks!​
Reptile [31]

Answer:

A=542

Step-by-step explanation:

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3 years ago
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(50 points + Brainliest for RIGHT answer).
ycow [4]
(-2, 0) and (0, -2)
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y = -x - 2

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y - 3 = -x - 5
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answer is A
y - 3 = -(x + 5)



5 0
4 years ago
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Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
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