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3 years ago

...........................

Mathematics

1 answer:

HACTEHA [7]3 years ago

4 0

Answer:

x>3

Step-by-step explanation:

Inequality Form:

x>3

Interval Notation:

(3,∞)

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The sum of the coordinates of the vertex of the parabola at y = x2 + 3 is _____.

Novosadov [1.4K]

Answer: The sum is 3.

Step-by-step explanation:

If we have a parabola, y = a*x^2 + b*x + c

We want to find the point (x, y) that corresponds to the vertex of that parabola.

The vertex of the parabola is at x value:

x = -b/2a

in this case

a = 1, b = 0, c = 3

then our vertex is at:

x = -0/2*1 = 0

Now we evaluate y(x) in this value and get:

y(0) = a*0^2 + 3 = 3

Then the vertex is at the point (0, 3)

the sum of the coordinates of the vertex is:

S = 0 + 3 = 3

7 0

3 years ago

Write a second inequality withe the same meaning -20 <- s

DedPeter [7]

S < 20 , -5x > -100 , etc

8 0

3 years ago

The table of values shown below represents a linear function. Which of these points could also be an ordered pair in the table,

maks197457 [2]

Answer:

(18,27) , because the rate of change of the function is $\frac{4}{3}$

Step-by-step explanation:

step 1

Find the slope of the linear equation

Looking at the table

we have the points (0,3) and (3,7)

The slope is equal to

$m=(7-3)/(3-0)=\frac{4}{3}$

step 2

Find the equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=\frac{4}{3}$

$b=3$ -----> point (0,3) is the y-intercept

substitute

$y=\frac{4}{3}x+3$

The rate of change of the linear equation is equal to $\frac{4}{3}$

Remember that

If a ordered pair is a solution of the linear equation, then the ordered pair must satisfy the linear equation

<u><em>Verify </em></u>

1) point (18,27)

substitute the value of x and the value of y in the linear equation

$27=\frac{4}{3}(18)+3$

$27=24+3$

$27=27$ -----> is true

The ordered pair is a solution of the linear equation

therefore

The point (18,27) could also be an ordered pair in the table

2) point (27,18)

substitute the value of x and the value of y in the linear equation

$18=\frac{4}{3}(27)+3$

$18=36+3$

$18 \neq 39$ -----> is not true

The ordered pair is not a solution of the linear equation

therefore

The point (27,18) could not be an ordered pair in the table

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alukav5142 [94]

Answer:

r<-8

Step-by-step explanation:

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I don’t understand this can someone help me

tatyana61 [14]

Answer:

$\sqrt[3]{432 {x}^{5} } \\ \\ 432 = 6 \times 6 \times 6 \times 2 = {6}^{3} \times 2 \\ {x}^{5} = x \times x \times x \times x \times x = {x}^{3} \times {x}^{2} \\ \\ \sqrt[3]{432 {x}^{5} } = 6x \sqrt[3]{2 {x}^{2} }$

I hope I helped you^_^

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3 years ago

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