Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
Answer:
0.075 sq km
Step-by-step explanation:
Given that there is a rectangular field with dimensions of length =300 m and width = 250 m.
We have to calculate area of this rectangle in the units of square kilometres.
Let us convert length and width into km
1000m = 1 km
Hence length = 300/1000= 0.3 km and
width = 250/1000 = 0.25 km.
ARea = length x width = 0.3 x 0.25
=0.075 square km.
Width= 8 cm
Because 192 / 2 = 96 / 12 = 8
SA= (perimeter * height) + 2 (length * width)
SA= (20*12)+2(2*8)
SA= 240+32
SA= 272 cm2
Answer:
I am pretty sure this statement is false so it'd be: x= 0
Step-by-step explanation:
