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2 years ago

Fill in the missing numbers to complete the pattern: 5.81, ,5.91,5.96, ,6.06

1 answer:

4 0

You’re going to be adding by .05

so the first one would be 5.86 and the second one would be 6.01

hopefully this helps!

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What is the answer to this

lianna [129]

Answer:

Step-by-step explanation:

$v = \pi \: d \\ \\ v = 14 \times \pi = 14\pi \: cm$

in this formula

d is diameter

v is circumference

because the question asked the answer in terms of pi so we write the pi its self

hope this help you

god bless you and us

7 0

2 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

3 years ago

I am stuck on this question of my maths test.

V125BC [204]

Answer:

angle y

58 + 38 + y = 180 (angle sum property)

96 + y = 180

y = 180 - 96

y = 84

angle x

x = 29 (58/2)

(angle subtended by an arc at centre is double the arc at any point on remaining part of centre)

the values of x = 29 and y = 84

6 0

2 years ago

Which problem situation can be represented by the equation below?

olasank [31]

I believe the answer is H,
Karen had a gift card for $150. She bought 3 gifts for her sister. The gifts cost the same amount, X. After paying for the gifts, her card had a balance of $60. How much did each gift cost?

5 0

2 years ago

11x+16y=13 solve for y

suter [353]

11x+16y = 13

16y = -11x+13

y = -11/16x+13/16

3 0

2 years ago