Question

Find the Laplace Transform of the following function. f(t) = 10 cos (12t+ 60°) u(t)

Answer 1

Answer:

L(f(t)) = $\frac{5s - 60\sqrt{3} }{s^2 + 144}$

Step-by-step explanation:

f ( t ) = 10 cos ( 12t + 60°) u(t)

attached below is a detailed solution of the given problem

L(f(t)) = $\frac{5s - 60\sqrt{3} }{s^2 + 144}$