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Gwar [14]
3 years ago
7

The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value o

f a population?
Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0

To obtain an estimate of a parameter of a population, we use confidence intervals.

Confidence intervals:

The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.

Thus, you should select the highest sample size in the options.

For more on confidence interval/margin of error, you can check brainly.com/question/22718960

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Answer:

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Step-by-step explanation:

We are given the inetegral:  \int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx

\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx=\int\limits^{\infty}_2 (\ln x)^2 d(\ln x)=\\\\=\lim_{t \to \infty} \int\limits^t_2 (\ln x)^2d(\ln x)=\lim_{t \to \infty} \frac{(\ln t)^3}{3} |^t_2=\infty-\frac{(\ln 2)^3}{3} =\infty

So it is divergent.

7 0
4 years ago
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Step-by-step explanation:

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3 years ago
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Jlenok [28]
Sometimes there is no apparent way to factor it by hand /(the factors are decimals or imaginary). To try and factor these problems is nearly impossible in your head.
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