Suppose the integers are n , n+2 , n+4 and n+6.
84=n+(n+2)+(n+4)+(n+6)=4n+12.
Subtract 12 from both ends to get.
72=4n.
Divide both ends by 4 to get.
n=18.
So the integers are: 18 , 20 , 22 , 24.
Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
Answer:
1)-5
2)-15
3)1
4)-11
5)-70
if negative use () for example
(-2)-7+4
Answer:
-20x+8
Step-by-step explanation:
Step 1: rearrange the equation
16x^2 - 3x^2 - 7x - 13x +8
Step 2: solve the equation
16x^2 - 3x^2 = 13x^2
-7x - 13x = -20x
(the +8 will stay the same)
so when we put it all together it gives us
13x^2 - 20x + 8
To solve for

You first need to find a common denominator.
To do so, you need to make both denominators 10 by multiplying the top and bottom of

by 5

=

Reduce by dividing both the top and bottom by 2
Your answer is