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Mandarinka [93]
2 years ago
6

To follow is information about the units produced and total manufacturing costs for Pine Enterprises for the past six months. Mo

nth Number of units produced Total manufacturing costs January 9000​ $8200​ February 7,500 $8,000 March 6,600 $7,550 April 6,800 $7,650 May 5000​ $6800​ June 7,000 $7,750Using the high-low method, what is the monthly fixed manufacturing cost
Business
1 answer:
sweet [91]2 years ago
4 0

Answer:

The monthly fixed manufacturing cost is $7500.

Explanation:

Variable cost per unit = change in total cost / change in no of units

                                    = 6900-5000/8000-4200  

                                    = 0.5 per unit

Fixed cost = Total manfacturing cost - variable cost at a 4200 level

                 = 5000 - (4200*0.5)

                 = 5000 - 2100

                 = $2900

If company produces 9200 units:  

Total manfacturing costs = fixed costs + 9200*variable cost per unit

                                          = 2900 + (9200*0.5)  

                                          = $7500

Therefore, The monthly fixed manufacturing cost is $7500.

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3 years ago
A fast-food restaurant has determined that the chance a customer will order a soft drink is 0.90. The proba- bility that a custo
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Answer:

(a) The probability that the order will include a soft drink and no fries is 0.45.

(b) The probability that the order will include a hamburger and fries is 0.48.

Explanation:

Let the events be denoted as follows:

S = an order of soft drink

H = an order of hamburger

F = an order of french fries.

Given:

P (S) = 0.90

P (H) = 0.60

P (F) = 0.50

(a)

It is provided that the event of ordering a soft drink and fries are independent.

If events A and B are independent then the probability of event (A ∩ B) is:

P(A\cap B)=P(A)\times P(B)

Compute the probability that the order will include a soft drink and no fries as follows:

P(S\cap \bar F)=P(S)\times P(\bar F)\\=P(S)\times[1-P(F)]\\=0.90\times (1-0.50)\\=0.45

Thus, the probability that the order will include a soft drink and no fries is 0.45.

(b)

It is provided that the conditional probability that a customer will order fries given that he/she has already ordered a hamburger as, P (F|H) = 0.80.

The conditional probability of an event B given another event A has already occurred is:

P(B|A)=\frac{P(A\cap B}{P(A)}

Compute the probability that the order will include a hamburger and fries as follows:

P(F|H)=\frac{P(H\cap F)}{P(H)}\\P(H\cap F)=P(F|H)\times P(H)\\=0.80\times 0.60\\=0.48

Thus, the probability that the order will include a hamburger and fries is 0.48.

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