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shutvik [7]
3 years ago
10

The data in which table represents a linear function that has a slope of zero?

Mathematics
2 answers:
Gekata [30.6K]3 years ago
3 0

Answer:

A 2-column table with 5 rows. Column 1 is labeled x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 5, 5, 5, 5. A 2-column table with 5 rows. Column 1 is labeled x with entries 1, 2, 3, 4, 5. Column 2 is labeled y with entries negative 5, negative 4, negative 3, negative 2, negative 1. A 2-column table with 5 rows. Column 1 is labeled x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 4, 3, 2, 1. A 2-column table with 5 rows. Column 1 is labeled x with entries 5, 5, 5, 5, 5. Column 2 is labeled y with entries negative 5, negative 4, negative 3, negative 2, negative 1.

Step-by-step explanation:

dont believe this

pls

dimulka [17.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

A 2-column table with 5 rows. Column 1 is labeled x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 5, 5, 5, 5. A 2-column table with 5 rows. Column 1 is labeled x with entries 1, 2, 3, 4, 5. Column 2 is labeled y with entries negative 5, negative 4, negative 3, negative 2, negative 1. A 2-column table with 5 rows. Column 1 is labeled x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 4, 3, 2, 1. A 2-column table with 5 rows. Column 1 is labeled x with entries 5, 5, 5, 5, 5. Column 2 is labeled y with entries negative 5, negative 4, negative 3, negative 2, negative 1.

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An arhitect wants to draw a rectangle with a diagonal of 20 inches. The length of the rectangle is to be 8 inches more than twic
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The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

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w = x

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Let's plug our numbers into the formula above.

20in = sqrt((x)^2 + (2x + 8)^2)

Let's simplify the inside of the sqrt

20 in = sqrt(5x^2 + 32x + 64)

Now, let's square both sides.

400 = 5x^2 + 32x + 64

Subtract 400 from both sides.

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Factor

0 = (5x - 28)(x + 12)

Set both terms equal to zero and solve.

x + 12 = 0

Subtract 12 from both sides.

x = -12

5x - 28 = 0

Add 28 to both sides.

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Divide both sides by 5

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The width cant be a negative number so now we know that the only real solution is 28/5

Let's plug 28/5 into our length equation.

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In conclusion,

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