The mat adds 3 inches to each side, so the length would be 3+20 = 23 inches. The width would become 3 + 9 = 12 inches.Area = Length x width:
23 x 12 = 276 square inches
Answer:
This equation is incorrect. The equation simplifies to -3=4 which is incorrect.
Step-by-step explanation:
3(-3)=-9. 3(2)=6
-9+6=-3
-3=4 FALSE
9514 1404 393
Answer:
sin(∅) = -√65/65
Step-by-step explanation:
The identities that relate the cotangent, the cosecant, and the sine are ...
csc² = 1 +cot²
sin = 1/csc
_____
For the given values, we find ...
csc(∅)² = 1 +cot(∅)² = 1 +8² = 65
csc(∅) = -√65 . . . . . . . . . . . . . . . . square root with attention to sign
sin(∅) = -1/√65 = (-√65)/65
#1 second line: x-y=-3
x=y-3(isolating x to prepare for substitution)(what x is equivalent to)
get back to the first line
x+y=5
(y-3)+y=5(substituting the value of x of the first line with the value of x at the second line)(It is a process to find the intersection between the two lines(line#1 and line#2 are two linear functions)
2y-3=5(simplify)
2y=8(simplify)
y=4(simplify)
line#1 x+y=5
x+(4)=5(plug the value of y back into either line#1 or line#2 will work)(plugging in the y value of the point of intersection to solve for the x value of the point of intersection)
x=1(solve)
the two linear lines intersect at the point(1(x coordinate), 4(y coordinate))(1,4)
#2 (line#1) y=3x-1
(line#2) 2x+y=14
2x+(3x-1)=14
5x-1=14
5x=15
x=3
y=3(3)-1
y=9-1
y=8
(3,8)
#3 line#1 2x+3y=8
line#2 6x+9y=24
2x=8-3y
x=(8-3y)/2
6((8-3y)/2)+9y=24
24-9y+9y=24
24=24
(those two lines are on top of yeach other/the same line)
any point on the line
#4 line#1 3x-4y=12
line#2 y=3/4x-4
3x-4(3/4x-4)=12
3x-3x+16=12
16=12
parallel lines: lines with same slope and different y-intercept
No solution/they never intercept each other
I hope it is helpful, if you have any question, I will answer ASAP
