Answer:
There is significant evidence at 0.05
Step-by-step explanation:
Given that:
After performing hypothesis., with confidence level being α = 0.05 ; The researcher decides to reject the Null. The conclusion will be ;
There is significant evidence to reject the Null at confidence level of 0.05
9514 1404 393
Answer:
2/5, 7/15, 8/15, 3/5, 2/3
Step-by-step explanation:
If these fractions are expressed with a common denominator, that would be 3×5 = 15. Then the given fractions are 1/3 = 5/15, and 4/5 = 12/15. The numerators 5 and 12 differ by 7, so we can easily choose 5 fractions in that range:
6/15 = 2/5
7/15
8/15
9/15 = 3/5
10/15 = 2/3
_____
<em>Alternate solutions</em>
There is no requirement for the fractions to be written any particular way or with any particular spacing. The limits in decimal are 1/3 = 0.3333...(repeating) and 4/5 = 0.8. We could choose the decimal fractions ...
0.34, 0.40, 0.50, 0.60, 0.70
or
0.41, 0.52, 0.63, 0.74, 0.79
Answer:
Tn = 4n+3
Step-by-step explanation:
It is an Arithmetic Sequence
a=7
d=11-7 =4
Tn= a+(n-1)d
= 7+(n-1)4
= 7+4n-4
= 4n+3
Answer: 91
Step-by-step explanation:
Given : The number of documentaries = 5
The number of comedies = 7
The number of mysteries = 4
The number of horror films =5
The total number of movies other than comedy = 14
Now, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is given by :-
Therefore, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is 91 .
Answer:
52b
Step-by-step explanation:
She has 52 cards per deck, and b decks.
This means she has 52b cards.
How this works:
For 1 deck, she has 52 cards, or 52×1 cards.
For 2 decks, she has 104 cards, or 52×1 cards.
For 5 decks, she has 260 cards, or 52×5 cards.
For 10 decks, she has 520 cards, or 52×10 cards.
Therefore, for b decks, she has 52×b, or 52b cards.
**This content involves writing algebraic expressions, which you may wish to revise. I'm always happy to help!
