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jeka94
3 years ago
9

Which graph shows the result of dilating this figure by a factor of 4 about the origin? On a coordinate plane, rectangle A B C D

has points (negative 1, 1), (3, 1), (3, negative 1), (negative 1, negative 1). On a coordinate plane, rectangle A prime B prime C prime D prime has points (negative 4, 4), (12, 4), (12, negative 4), (negative 4, negative 4). On a coordinate plane, rectangle A prime B prime C prime D prime has points (negative 2, 2), (6, 2), (6, negative 2), (negative 2, negative 2). On a coordinate plane, rectangle A prime B prime C prime D prime has points (negative 0.25, 0.25), (0.75, 0.25), (0.75, negative 0.25). (negative 0.25, negative 0.25). On a coordinate plane, rectangle A prime B prime C prime D prime has points (negative 0.5, 0.5), (1.5, 0.5), (1.5, negative 0.5), (negative 0.5, negative 0.5). Mark this and return
Mathematics
1 answer:
dybincka [34]3 years ago
5 0

Answer:

a

Step-by-step explanation:

please mark me brainliest.

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A tire with a radius of 22 centimeters
kozerog [31]
The answer will be 138.16

You will find the answer by multiplying by 2 and 22 which will give you  44, then you multiply that but 3.14 which will give you 138.16
6 0
3 years ago
7/6 - 4/3n = -3/2n + 2(n + 3/2)
blagie [28]
2n/3+25/6 I simplified the question if that is  what you wanted me to do.
7 0
3 years ago
Solve for x.
crimeas [40]

Answer:

x = 11/10

Step-by-step explanation:

5(2x - 1) = 6

Distribute

10x -5 = 6

Add 5 to each side

10x-5+5 = 6+5

10x = 11

Divide each side by 10

10x/10 = 11/10

x = 11/10

7 0
3 years ago
6) Two boats set off from X at the same
lord [1]

Answer:

The distance between the two boats after 2.5 hours is 57 m.

Step-by-step explanation:

The distance covered by each boat after 2.5 hours are:

speed = \frac{distance}{time}

distance = speed x time

For boat A, speed = 14 km/h and time = 2.5 hrs.

So that,

distance = 14 x 2.5

              = 35 km

For boat B, speed = 18 km/h and time = 2.5 hrs.

So that,

distance = 18 x 2.5

              = 45 km

The distance between the two boats after travelling 2.5 hours can be determined by applying the cosine rule. Let the distance be represented by x, so that:

a^{2} = b^{2} + c^{2} - 2bc Cos A

x^{2} = 45^{2} + 35^{2} - 2(45 x 35) Cos 90^{o}

   = 2025 + 1225 - 3150 (0)

   = 3250

x = \sqrt{3250}

  = 57.0088

x = 57.0 m

The distance between the two boats after 2.5 hours is 57 m.

4 0
3 years ago
For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 35 N acts on
Genrish500 [490]
<h3>Answer:  3 m/s^2</h3>

=======================================================

According to Newton's Second Law, we know that

F = m*a

where F is the force applied, m is the mass and 'a' is the acceleration.

We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.

Plug in F = 35 and a = 5 to find m

F = ma

35 = m*5

35/5 = m

7 = m

m = 7

The object has a mass of 7 kg

Our equation F = ma updates to F = 7a

Now plug in the force F = 21 to find 'a'

F = 7a

21 = 7a

21/7 = a

3 = a

a = 3

The acceleration will be 3 m/s^2

Notice how a smaller force applied means that the acceleration has also gone down as well.

8 0
3 years ago
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