Pessoal oque eu vou colocar aqui não é uma questão é apenas uma dúvida que eu gostaria de tirar:

5) Suppose a slice of a 12-inch pizza has an area of 20 square inches. What is the angle of

devlian [24]

Answer:

The angle of the slice is 63.64 degrees

Step-by-step explanation:

Here in this question, we are concerned with calculating the angle of the slice.

What we should know are as follows;

1. A pizza is a perfect circular shape

2. A 12-inch pizza means the diameter of the pizza is 12 inches and consequently its radius will be 12/2 = 6 inches

3. A slice of a pizza represents a sector of the circle( a sector is part of a circle bounded by 2 radii and an arc)

Mathematically, to calculate the angle of the slice, we simply use the formula for the area of a sector.

Area of sector = theta/360 * pi * r^2

where Area of sector = 20 square inches

theta is the center angle we are looking for

r is the radius of the pizza which is 6 inches

Plugging these values into the area of sector equation, we have

20 = theta/360 * 22/7 * 6^2

20 = theta/10 * 22/7

22 theta = 10 * 20 * 7

theta = 1400/22

theta = 63.64 degrees which is approximately 64 degrees to the nearest degree

5 0

4 years ago

Consider the line 7x+4y= 3. What is the slope of a line parallel to this line? What is the slope of a line perpendicular to this

kirza4 [7]

Answer:

1) -7/4

2) 4/7

3) -1/5

Step-by-step explanation:

1) A parallel line would have the same gradient so:

4y = -7x +3
y = $\frac{-7}{4}x +\frac{3}{4}$

So a parallel line would have the gradient of $\frac{-7}{4}$ .

2) A perpendicular line would have the inverse reciprocal of the gradient so multiplying the 2 gradients would equal -1 so:

Initially Gradient = -7/4

-7/4 x Perpendicular line = -1

Perpendicular line = -1 x 4/-7

Perpendicular line = 4/7

3) Using the same principle, the perpendicular gradient would be -1/5x

3 0

2 years ago

Which equation represents the line that passes through (–6, 7) and (–3, 6)? y = –y equals negative startfraction one-third endfr

egoroff_w [7]

The equation represents the line that passes through (–6, 7) and (–3, 6) $\rm y=\dfrac{-1}{3}x+5$ .

<h3>What is the slope of the equation?</h3>

For all lines in slope y-intercept form, it would be very simple to just find the answer by finding yourself the slope and y-intercept of the line in question.

The slope of the line is;

$\rm m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m =\dfrac{7-6}{-6-(-3)}\\\\m = \dfrac{1}{-3}$

The equation represents the line that passes through (–6, 7) and (–3, 6) is;

$\rm y=\dfrac{-1}{3}x+b\\\\6=\dfrac{-1}{3}(-3)+b\\\\6=1+b\\\\b = 6-1\\\\b=5$

The required line of the equation is;

$\rm y =mx+c\\\\y=\dfrac{-1}{3}x+5$

Hence, the equation represents the line that passes through (–6, 7) and (–3, 6) $\rm y=\dfrac{-1}{3}x+5$ .

To know more about the equation of line click the link given below.

brainly.com/question/8955867

3 0

2 years ago

If f(x) = 4x – 3 and g(x) = 8x + 2, find each function value

vladimir1956 [14]

Answer:

f[g(3)] = 100

g[f(5)] = 138

g{f[g(-4)]} = -982

Step-by-step explanation:

f(x) = 4x - 3

g(x) = 8x + 2

a. f[g(3)]

First find g(3) by putting x = 3 in g(x) function

g(3) = 8(3) + 2 = 24 +2 = 26

now put this g(3) = 26 as x in f(x)

f(g(3)) = f(26) = 4(26) - 4 = 104 - 4 = 100

b. g[f(5)]

First lets find f(5)

f(x) = 4x - 3

put x = 5 above

f(5) = 4(5) - 3 = 20 - 3 = 17

put this f(5) = 17 as x in g(x)

g(f(5)) = g(17) = 8(17) + 2 = 138

c.g{f[g(-4)]}

First lets solve the inner most function

g(-4) = 8(-4) +2 = -30

put g(-4) = -30 in f(x) to find f(g(-4))

f(g(-4)) = f(-30) = 4(-30) - 3 = -123

put f(g(-4)) = -123 as x in g(x) to find our complete result

g{f[g(-4)]} = g(-123) = 8(-123) + 2 = -982

4 0

4 years ago

For the following, find f(g(x)) and g(f(x)).<br> f(x) = 3x - 1<br> G(x) = 2x - 1/ x

Ronch [10]

Step-by-step explanation:

by comparing both f (x) and g (x)

we get

3x-1=2x-1/x

by this way we can get the value of X and put the value of X in f (x) and g (x)

4 0

2 years ago