Answer:
c
Step-by-step explanation:
hello :
<span>(-101)+102+(-103)+104+...+(-199)+200
=( </span>(-101)+(-103) +....+ (-199) ) +( (102) + ( 104) +....+(200))
let : A = ( (-101)+(-103) +....+ (-199) )
B = ( (102) + ( 104) +....+(200))
note : the sum n term of arithemtic sequence
S= n/2(u1 + un)
un = u1 +(n-1) d u1 : the first term d : the common diference
in A : u1= -101 d = -2 n = 49...
in B : u1 =102 d=2 n= 49
A = 49/2(-101-199) =-7350
B=49/2(102+200)=4949
(-101)+102+(-103)+104+...+(-199)+200 = A+B =-2401
We know that point M is a midpoint of segment RS, and line l passes through segment RS. Since l passes through RS at its midpoint, M, then we can declare that l is the bisector of RS. Your best answer is A since the above is the basic definition of a bisector.
"Ten less" means that we subtract 10. "Quotient" means that we divide.
(x / 3) - 10 = 6
I can show you how to solve for x.
Add 10 on both sides of the equation.
x / 3 = 16
Multiply both sides of the equation by 3.
x = 48
I hope I helped :)
144. 3^2 * 4^2. 9 * 16 = 144