A sign has 64 rows<span> of </span>lights<span> with </span>128 lights<span> in </span>each row<span>. How </span>many lights<span> are on - 685853. ... on the </span>sign<span>? </span>Choose exactly two answers<span> that are </span>correct<span>. A. </span>multiplication B<span>. </span>division C<span>. </span>2 D<span>. </span>8,192<span>. 1 ... </span>128 light each<span>. (or </span>128 rows<span> with </span>64 light each<span>) so per </span>each row<span> there are </span>128<span> so </span>64<span>* </span>128<span>give the total </span>answer.<span>A </span>sign has 64 rows<span> of </span>lights<span> with </span>128 lights<span> in </span>each row<span>. How </span>many lights<span> are on - 685853. ... on the </span>sign<span>? </span>Choose exactly two answers<span> that are </span>correct<span>. A. </span>multiplication B<span>. </span>division C<span>. </span>2 D<span>. </span>8,192<span>. 1 ... </span>128 light each<span>. (or </span>128 rows<span> with </span>64 light each<span>) so per </span>each row<span> there are </span>128<span> so </span>64<span>* </span>128<span>give the total </span>answer<span>.</span>
Answer:
7∠82°
Step-by-step explanation:
Well angle 6 and 7 are complementary angles, meaning they both add up to 180°.
So we do 180 - 98 which is 82°.
So firstly, the three terms share a GCF of x, so factor that out: 
Next, I'm going to be factoring by grouping. But first, what two terms have a product of 140x^2 and a sum of 33x? That would be 28x and 5x. Replace 33x with 5x + 28x: 
Now factor 20x^2 + 5x and 28x + 7 separately, make sure that they have the same quantity on the inside: ![x[5x(4x+1)+7(4x+1)]](https://tex.z-dn.net/?f=%20x%5B5x%284x%2B1%29%2B7%284x%2B1%29%5D%20)
<u>Now you can rewrite the expression as ![x[(5x+7)(4x+1)]](https://tex.z-dn.net/?f=%20x%5B%285x%2B7%29%284x%2B1%29%5D%20)
, which is your final answer.</u>
