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never [62]
3 years ago
9

P(AB)

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0
The answer is 10/1
There are 10 boys and 1 of them is a sophomore
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Please answer this question now
Rashid [163]

Answer:

54

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

Thus,

IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

4 0
3 years ago
What rule describes this transformation? *
Blizzard [7]

Answer:

(x,y) -> (-x,y)

Step-by-step explanation:

The image is flipped over the x axis.

8 0
3 years ago
Which of the following is a radical equation?
MrMuchimi
It is A because it can’t be B and it can’t be C and it can’t be D so my answer is A
5 0
3 years ago
Jeff is baking a cake. The recipe says that he has to mix 32 grams of vanilla powder to the flour. Jeff knows that 1 cup of that
Sedaia [141]

Answer:

Jeff went over by 53.33 grams or 53\frac{1}{3} grams.

Step-by-step explanation:

Jeff is baking a cake. The recipe says that he has to mix 32 grams of vanilla powder to the flour.

Jeff knows that 1 cup of that particular vanilla powder has a mass of 128 grams.

He added \frac{2}{3} of a cup of vanilla powder to the flour.

So, he added a mass of \frac{2}{3} \times128= 85.33 grams of vanilla.

As the recipe says, it needs 32 grams of vanilla so Jeff went over by 85.33-32=53.33 grams.

Jeff went over by 53.33 grams or 53\frac{1}{3} grams.

8 0
3 years ago
Find upper and lower limit of a weight of a cotton reel which is 1.56g nearst to mg
Papessa [141]

Answer: the lower limit is 1.555g and the upper limit is 1.564g

Step-by-step explanation:

a mg is:

1mg = 0.001g

Then we need to look at the third digit after the decimal point.

Then the weight 1.56g is rounded around this.

Remember that if the third digit after the decimal point is 5 or bigger, then we round up.

if the third digit is smaller than 5, then we round down.

Now, the maximum possible value of this weight is when the third digit is equal to 4 (4 mg) where because it is smaller than 5, we round it down to 1.56g

Then the maximum is 1.564g

And the minimum value is when we have:

w = 1.555g

Because the third digit is a 5, we round it up to 1.56g.

So the lower limit is 1.555g and the upper limit is 1.564g

4 0
3 years ago
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