Difference of 2 perfec squares is
(a^2)-(b^2)
if the exponents are both even and the coeficient (the number in front) are perfect squares, then it is difference t 2 perfect squares
first one
8 is not perfect square
2nd one
(4e^4)^2-(9g^2)^2
third
25 is odd, so it cannot be split up into 2 nice numbers
4th
(11m^9)^2-(3n^5)^2
Answer:
Step-by-step explanation:
so whats the answer?
Answer:
Explanation:
We must write this equation in the form
(
x
−
a
)
2
+
(
y
−
b
)
2
=
r
2
Where
(
a
,
b
)
are the co ordinates of the center of the circle and the radius is
r
.
So the equation is
x
2
+
y
2
−
10
x
+
6
y
+
18
=
0
Complete the squares so add 25 on both sides of the equation
x
2
+
y
2
−
10
x
+
25
+
6
y
+
18
=
0
+
25
=
(
x
−
5
)
2
+
y
2
+
6
y
+
18
=
0
+
25
Now add 9 on both sides
(
x
−
5
)
2
+
y
2
+
6
y
+
18
+
9
=
0
+
25
+
9
=
(
x
−
5
)
2
+
(
y
+
3
)
2
+
18
=
0
+
25
+
9
This becomes
(
x
−
5
)
2
+
(
y
+
3
)
2
=
16
So we can see that the centre is
(
5
,
−
3
)
and the radius is
√
16
or 4
I’m not 100% sure but I think it’s because 20/25 can still be simplified further, while the other 3 can’t.
