Question 5 pleaseeee
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The graph of the solution set for the inequality can be seen below.
<h3>How to graph the solution set?</h3>Here we have the inequality:
3x - 2y < -12
If we isolate y, we get:
3x + 12 < 2y
(3x + 12)/2 < y
(3/2)x + 6 < y
Now, we just need to graph the line y = (3/2)x + 6 with a dashed line (because the points on the line are not solutions).
And then we need to shade the region above the line.
The graph of the solution set can be seen below.
If you want to learn more about inequalities:
#SPJ1
Given:
PQRS is a rectangle and XY is parallel to PS.
RY = 9 cm, QR = a cm and YS = b cm
Area of PQRS = 84 cm²
Area of PXYS = 21 cm²
To find:
The value of a and b.
Solution:
RS = 9 + b
Area of rectangle = length × width
Area of PQRS = QR × RY
QR × RS = 84
----------- (1)
Area of PXYS = XY × PS
XY × PS = 21
(since QR = XY)
----------- (2)
Substitute (2) in (1).
Subtract 21 from both sides, we get
Divide by 9 on both sides, we get
a = 7
Substitute a = 7 in (2).
Divide by 7 on both sides, we get
b = 3
The value of a is 7 cm and b is 3 cm.