Question 5 pleaseeee

Mathematics

1 answer:

vovikov84 [41]3 years ago

3 0

Answer:

first

Step-by-step explanation:

f(n) =56 (0.5)^(n-1)

f(1) = 56 (0.5)^0= 56*1 = 56

f(2) =56 (0.5)^1 = 56* 0.5 = 28

f(3) = 56 (0.5)^2 = 14

f(4) = 56 (0.5)^3 = 7

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The interquartile range of the data is equal to 2.18.

<h3>What is an interquartile range?</h3>

The interquartile range is a measure of where a data set's "middle fifty" is located. Whereas a range is a measure of where the start and end of a set are, an interquartile range is a measure of where the majority of the values are.

Given data is { 1.56,1.77,2.22,2.35,2.45,2.77,3.26,4.35,5.23,6.02}.

The upper limit is, and the median is 2.22.

{ 1.56,1.77,<u>2.22</u>,2.35,2.45,2.77}

The lower limit is, and the median is 4.35.

{2.77,3.26,<u>4.35</u>,5.23,6.02}

The interquartile range will be calculated as,

IQR = 4.35 - 2.22

IQR = 2.18

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