All categories

2 years ago

Respiration eliminates excess _______ from the body.

Biology

2 answers:

faltersainse [42]2 years ago

7 0

Answer:

Explanation:

This is because the body inhales oxygen and exhales carbon-dioxide through the process of respiration

stellarik [79]2 years ago

4 0

Answer:

Carbondioxide.

Explanation:

...............

You might be interested in

Synthesis of proteins is

babymother [125]

Phenomena of amino acid assembly from RNA. The synthesis of proteins from RNA is known as translation. In eukaryotes, translation occurs in the cytoplasm, where the ribosomes are located. Ribosomes are made of a small and large subunit that surround the mRNA.

6 0

2 years ago

Salmonberry leaf cells contain 14 chromosomes. How many chromosomes will a new leaf cell contain after mitosis ?

Mama L [17]

The new leaf will contain 14 chromosomes, because during mitosis, a cell makes an exact copy of itself. Therefore, the number of the chromosomes in that cell stay the same.

7 0

3 years ago

Read 2 more answers

Which of these is not one of rusbult and colleagues' (1986, 1987, 1998) three ways of coping with a failing relationship?

Sindrei [870]

Pragma <span>is not one of rusbult and colleagues' (1986, 1987, 1998) three ways of coping with a failing relationship.
</span>Pragma<span> is a pragmatic, practical, mutually beneficial relationship. The EVLN framework was developed by rustbult and her colleagues for personal love and marriage relationships.</span>

8 0

2 years ago

Carbon cycle pls help me

insens350 [35]

carbon dioxide Coronavirus

4 0

2 years ago

Black fur (B) is dominant to white fur (b) in guinea pigs. An F1 cross was conducted and resulted in 100% heterozygous guinea pi

Lemur [1.5K]

Answer:

D. 1 BB : 2 Bb : 1 bb

Explanation:

This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.

If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:

Bb = B and b

Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:

1 BB : 2 Bb : 1 bb

BB and Bb = black fur guinea pigs

bb = white fur guinea pigs

3 0

2 years ago