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boyakko [2]
3 years ago
10

Question 4: Subtract the following polynomials in this equation.

Mathematics
1 answer:
charle [14.2K]3 years ago
7 0

Answer:

c

Step-by-step explanation:

(x²-3x+8)-(7x²-2x-1)

x²-3x+8-7x²+2x+1

x²-7x²-3x+2x+8+1

-6x²-x+9

tq

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2.4 + 5.4q – 4.5q + 3.6<br><br> a.6+1.1q<br> b.9.9q+6<br> c.0.9q+6<br> d.9.9q-6
Yuri [45]
You have to add the same kind of terms, in this case the ones that have a variable (5.4q and -4.5q) and the ones that don't (2.4 and 3.6), like this:

(5.4q - 4.5q) + (2.4 + 3.6) = 0.9q + 6

The answer is c. 0.9 +6

8 0
3 years ago
120 times 1.75 show your work plz help me I really dont get it
sineoko [7]
120 * 1.75 = 200

5 times 0 = 0

5 times 2 = 10 carry the 1

5 times 1 = 5 + 1 = 6

7 times 0 = 0

7 times 2 = 14 carry the 1...

7 times 1 = 7 + 1 = 8
1 times 0 = 0
1 times 2 = 2
1 times 1 = 1
add it all together and you get 200.
6 0
3 years ago
Does the table represent a proportional relationship? Show your work!
wel
Yes, adding going up one every time, 5,6,7,8
4 0
3 years ago
How do you divided 3 by 927
Nostrana [21]
The answer 309
You jus literally divide 927/3 and get 309
7 0
3 years ago
Read 2 more answers
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
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