(12,1):12³+1³=1728+1=1729
(10,9): 10³+9³=1000+729=1729
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First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
Answer:
help with what
Step-by-step explanation:
It is more than one I think because it becomes -1 over -12 WITHOUT the -power and then add the power and it becomes positive. Make the power positive and it will become negative making it less than 1.
Answer:
The answer is -a-bc+43
Step-by-step explanation:
Pull terms out from under the radical, assuming positive real numbers